63x^2=-4(17x+3)

Solution for 63x^2=-4(17x+3) equation:

63x^2=-4(17x+3)

We move all terms to the left:

63x^2-(-4(17x+3))=0


We calculate terms in parentheses: -(-4(17x+3)), so:

-4(17x+3)

We multiply parentheses

-68x-12

Back to the equation:

-(-68x-12)


We get rid of parentheses

63x^2+68x+12=0

a = 63; b = 68; c = +12;
Δ = b2-4ac
Δ = 682-4·63·12
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-40}{2*63}=\frac{-108}{126}
=-6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+40}{2*63}=\frac{-28}{126}
=-2/9
$